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5u^2+17u-12=0
a = 5; b = 17; c = -12;
Δ = b2-4ac
Δ = 172-4·5·(-12)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-23}{2*5}=\frac{-40}{10} =-4 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+23}{2*5}=\frac{6}{10} =3/5 $
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